a bus starts to move with an acceleration 1m per second square a man who is 48m behind the bus runs with constant velocity of 10 m/s torech it. in how much time he will catch the bus
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Answer:
8 sec
Explanation:
total distance travelled by man with uniform speed 10ms^-1 is , 48+s=10(t)_______1
distance travelled by bus from rest in t,s=1/2at^2=t^2/2_______2
from 1 and 2:
48+t^2/2=10t
just simplify, hence (t-8)(t-12)=0
t=8(or)12 sec
so the man catches in 8 sec
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