Question

a bus starts to move with an acceleration 1m per second square a man who is 48m behind the bus runs with constant velocity of 10 m/s torech it. in how much time he will catch the bus

Answer 1

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Answer 2

Answer:

8 sec

Explanation:

total distance travelled by man with uniform speed 10ms^-1 is , 48+s=10(t)_______1

distance travelled by bus from rest in t,s=1/2at^2=t^2/2_______2

from 1 and 2:

48+t^2/2=10t

just simplify, hence (t-8)(t-12)=0

t=8(or)12 sec

so the man catches in 8 sec