A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is f 12 per m2, what will be the cost of painting ail the cones?
Answers
Answer:
Cost of painting 50 cones is Rs. 384.33
Step-by-step explanation:
Given :
Height of cone = 1 m
Base Diameter = 40 cm
∴ Radius =
= .2 m
Consider l as the slant height
l² = h² + r²
l² = (1)² + (0.2)²
l² = 1 + 0.04 = 1.04
Taking square toot on both sides we get,
l = √1.04 = 1.02 m
Curved surface area of 1 cone = πrl
= 3.14 x 0.2 x 1.02 m²
=0.64056m²
Total curved surface area of 50 cones = 50 x 0.63056 = 32.028 m²
Cost of painting = 12 per m²
Total cost of painting 50 cones = 12 x 32.028 = Rs. 384.33
To Learn More....
1. Yhe total surface area of cone is 71.28 cm2 find the volume of its cone if the diameter of base 5.6cm
https://brainly.in/question/8394949
2. The curved surface area of cone is 670 CM square and its radius is 15 CM then its total surface area is
https://brainly.in/question/5064128
Given:-
- No. of Cones = 50
- Diameter = 40 cm = 0.4 m
- Radius = 0.2 m
- Height = 1 m
step-by-step explaination:-
Radius of the cone (r) = 40/2 cm = 20 cm = 0.2 m
Height of the cone (h) = 1 m
• Let l be the slant height of a cone.
- ∴ l = √h² + r²
- ⇒ l = √12 + 0.22
- ⇒ l = √1.04
- ⇒ l = 1.02 m
Rate of painting = ₹12 per m²
Curved surface of 1 cone = πrl m²
= (3.14 × 0.2 × 1.02) m²
= 0.64056 m²
Curved surface of such 50 cones
= (50 × 0.64056) m²
= 32.028 m²
Cost of painting all these cones
= ₹(32.028 × 12)
= ₹384.34
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hope it helps buddy : )
