A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is f 12 per m2, what will be the cost of painting ail the cones?
Answers
Given:-
No. of Cones = 50
Diameter = 40 cm = 0.4 m
Radius = 0.2 m
Height = 1 m
step-by-step explaination:-
Radius of the cone (r) = 40/2 cm = 20 cm = 0.2 m
Height of the cone (h) = 1 m
• Let l be the slant height of a cone.
∴ l = √h² + r²
⇒ l = √12 + 0.22
⇒ l = √1.04
⇒ l = 1.02 m
Rate of painting = ₹12 per m²
Curved surface of 1 cone = πrl m²
= (3.14 × 0.2 × 1.02) m²
= 0.64056 m²
Curved surface of such 50 cones
= (50 × 0.64056) m²
= 32.028 m²
Cost of painting all these cones
= ₹(32.028 × 12)
= ₹384.34
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hope it helps buddy : )
Step-by-step explanation:
Given:-
No. of Cones = 50
Diameter = 40 cm = 0.4 m
Radius = 0.2 m
Height = 1 m
step-by-step explaination:-
Radius of the cone (r) = 40/2 cm = 20 cm = 0.2 m
Height of the cone (h) = 1 m
• Let l be the slant height of a cone.
∴ l = √h² + r²
⇒ l = √12 + 0.22
⇒ l = √1.04
⇒ l = 1.02 m
Rate of painting = ₹12 per m²
Curved surface of 1 cone = πrl m²
= (3.14 × 0.2 × 1.02) m²
= 0.64056 m²
Curved surface of such 50 cones
= (50 × 0.64056) m²
= 32.028 m²
Cost of painting all these cones
= ₹(32.028 × 12)
= ₹384.34