A bus stop is barricated from the remaining part of the road, by using 50 hollow cones made of recycled cardboard .Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is rupees12 per meter square, what will be the cost of painting all these cones ? ( use pie = 3.14 and take root 1.04 = 1.02 ).
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Answer:
Curved surface area of cone will be painted=πrl
h=1m;radius=
2
40
=20cm=0.2m
and let l be the slant height,
∴l
2
=h
2
+r
2
=1
2
+0.2
2
⇒l=
1+0.04
=
1
.04=1.02m (∵
1
.04=1.02 is given in the question)
⇒Curved surface area of 1 cone=πrl=(3.14×0.2×1.02)m
2
=0.64046m
2
⇒ Curved surface area of 50 cones=50×0.64046=32.028m
2
Cost of painting 1m
2
=Rs.12
∴ Cost of painting 32.028m
2
=(12×32.028)=384.336m
2
≈384.34
∴ Cost of painting 50 cones is Rs.384.84
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