Math, asked by Abhishek1400V, 10 months ago

A bus takes 48 minutes to cover a certain distance when travelling at a speed of 50km/h. How much time will it take to cover the same distance when travelling at speed of 30km/h?

Answers

Answered by Cynefin
7

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Required Answer:

♦️ GiveN:

  • Firstly, the bus was travelling at a speed 50 km/h
  • It travels for 48 minutes.

♦️ To FinD:

  • Time taken to cover same distance at a speed of 30 km/h

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How to Solve ?

In the first case, with speed 50 km/h and time 48 minutes, we can find the distance by using formula.

\large{ \boxed{ \rm{ \pink{speed =  \frac{distance}{time} }}}}

Now, after getting the distance, we have to find the time taken with 2nd speed i.e. 30 km/h by using the same formula / speed, distance and time relation.

So, Let's find the solution of the problem....

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Solution:

Firstly, let's do some unit conversion because speed in km/hr whereas time is in minutes. So, converting time in minutes to time in hour.

We know,

\large{ \rm{ \longrightarrow \:60 \: minutes = 1 \: hour}} \\  \\ \large{ \rm{ \longrightarrow \: 1 \: minute =  \frac{1}{60} hour}} \\  \\  \large{ \rm{ \longrightarrow \: 48 \: minutes =   \cancel{\frac{48}{60} }hour =  \frac{4}{5} \: hour }}

We can rewrite the formula as,

\large{ \rm{ \ast{ \green{ \: distance = speed \times time}}}}

By using formula,

\large{ \rm{ \longrightarrow \: distance = 50 \: km {h}^{ - 1}  \times  \frac{4}{5} hr}} \\  \\ \large{ \rm{ \longrightarrow \: distance =  { \boxed{ \rm{40 \: km}}}}}

Now, as we got the distance = 40 km and the 2nd speed of the body = 30 km/hr, we can find the time.

We can rewrite the formula as,

 \large{ \rm{ \ast{ \green{time =  \dfrac{distance}{speed} }}}}

By using formula,

\large{ \rm{ \longrightarrow \: time =  \frac{40 \: km}{30 \: km {h}^{ - 1} } }} \\  \\  \large{ \rm{ \longrightarrow \: time =  \frac{4}{3} hr =  \boxed{ \red{ \rm{1. \overline{33 }\: hr}}}}} \\  \\  \large{ \therefore{ \underline{ \underline{ \rm{ \purple{Hence, \: solved \:  \dag}}}}}}

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Answered by TheSentinel
55

\purple{\underline{\pink{\boxed{\boxed{\red{\star{\sf Question:}}}}}}} \\ \\

\rm{A \ bus \ takes \ 48 \ minutes \ to \ cover \ a \ certain}

\rm{distance \ when \ traveling \ at \ a \ speed \ of }

\rm{50 \ km \ hr^-1 . \ How \ much \ time \ will \ it \ take}

\rm{to \ cover \ the \ same \ distance \ when \ traveling}

\rm{at \ speed \ of \ 30 \ km \ hr^-1 \ ?}

_________________________________________

\purple{\underline{\orange{\boxed{\boxed{\green{\star{\sf Answer:}}}}}}} \\ \\

\bf{\green{\therefore{\orange{Time \ taken \ by \ the \ bus \ to \ cover \ the }}}}

\bf{\green{\orange{same \ distance }}}

\bf{\green{\boxed{\orange{  =  \ \frac{4}{3} hr \ = \ 1.33 \ hr }}}} \\  \\

_________________________________________

\sf\large\underline\pink{Given:} \\ \\

\rm{Initially,} \\

\rm{ Time \ taken \ by \ a \ bus \ to \ cover \ certain }

\rm{distance}

\rm\implies{T \ = \ 48 \ min} \\ \\

\rm\implies{Speed \ of \ the \ bus : \ (S) \ 50 \ km \ hr^-1}

_________________________________________

\sf\large\underline\blue{To \ Find} \\ \\

\rm{Time \ taken \ by \ the \ bus \ to \ cover \ the \ same }

\rm{distance \ at \ speed \ of \ 30 \ km \ hr^-1}

_________________________________________

\green{\underline{\red{\boxed{\boxed{\purple{\star{\sf Solution:}}}}}}}

\rm{ initially \ the \ speed \ of \ the \ bus \ is : \ 50 \ kmhr^-1}

\rm{and}

\rm{ Time \ taken \ by \ a \ bus \ to \ cover \ certain }

\rm{distance : \ T \ = \ 48 \ min} \\ \\

\rm{We \ know ,} \\ \\

\rm{\implies{60 \: minutes  \ = \  1 \: hour}} \\  \\

\rm{\implies{ 1 \: minute =  \frac{1}{60} hour}} \\  \\

\rm{\implies{  48 \: minutes \  =  \  \cancel{\frac{48}{60} }hour =  \frac{4}{5} \: hour }}

\rm{also,}

\rm{\therefore{\green{\boxed{\purple{  distance = speed \times time}}}}} \\ \\

\rm{\implies{ distance = 50 \: km {h}^{ - 1}  \times  \frac{4}{5} hr}} \\  \\

\rm{\therefore{\orange{\boxed{distance \ = \ 40 \ km}}}} \\

\rm{we \ are \ also \ given \ that }

\rm{the \ speed \ of \ bus \ changes \ to \ 30 \ km \ hr^-1}

\rm{\therefore{\green{\boxed{\purple{time =  \frac{distance}{speed} }}}}}

\rm{\implies{ Time  \ = \   \frac{40 \: km}{30 \: km {hr}^{ - 1} } }} \\  \\

\rm\implies{Time \ = \ \frac{4 \ km}{3 \ km {hr}{-1}} \ = \ 1.33 }

\bf{\green{\therefore{\orange{Time \ taken \ by \ the \ bus \ to \ cover \ the }}}}

\bf{\green{\orange{same \ distance }}}

\bf{\green{\boxed{\orange{  =  \ \frac{4}{3} hr \ = \ 1.33 \ hr }}}} \\  \\

___________________________________________

\rm\red{Hope \ it \ helps \ :))}

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