Question

A bus to decreases its speed from 80 km per hr 60 km h in 5 second. find the acceleration of the bus.

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Answer 1

Answer:

The acceleration of the bus is -1.12m/s.

Explanation:

Acceleration a = (V - U) / t

Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.2 m/sec

Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.6 m/sec

Acceleration a = (V - U) / t

= (16.6 - 22.2)/5

= -5.6/5

= -1.12 m/s2

Negative sign indicates retardation.

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Answer 2

Answer:

-1.11m/s².

Explanation:

Initial velocity of a bus = 80km/h.

Final velocity of a bus = 60km/h.

Time = 5s.

In this question, we can see that speed of a bus is given in km/h and we have to convert it into m/s.

To convert speed from km/h to m/s we have to multiply the given speed by the fraction 5/18.

Let's do:-

Initial velocity = 5/18 × 80 = 22.22m/s.

Final velocity = 5/18 × 60 = 16.66m/s.

A/Q,

Acceleration = change in speed/time

a = v - u/t

⇢ a = (16.66 - 22.22)/5

⇢ a = -5.56/5

⇢ a = -1.11m/s²

Since speed decreases, retardation will take place. Retardation means negative acceleration.

∴ Acceleration of a bus is -1.11m/s².

Used Abbreviations

⇢ v = Final velocity.

⇢ u = Initial velocity.

⇢ t = time.

Additional Information

⇢ Three Equations of Motion

⇢ v = u + at.

⇢ s = ut + ½ at².

⇢ v² = u² + 2as.

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