Question

a bus travel ls the first one third distance at speed of 10 kph the next 20 kph and next 6 kph the average speed?

Answer 1

Let total distance =3S

The first S part is traveled with speed 10kmph

So time=t1 = distance/speed = S/10

The second S part is traveled with speed 20kmph

Time=t2=S/20

Time for third S part

t3=S/6

So total time =t1+t2+t3 = S/10 +S/20 +S/6

=(6S+3S+10S)/60

=19S/60

Now///

Average Speed =Total distance/Total Time

Total Time=19S/60

Total distance =3S

Average speed=3S/(19S/60)

=180S/19S

=9.47kmph

Answer 2

9.47 kmph if it is correct please follow me and Mark it as brainy please.