A bus traveled a certain average speed for a distance and then travels a distance 90 km at an average speed 10 km/h more than first speed if it takes 3 hours to complete whole journey find first speed
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Solution :
Distance travelled by the bus = 75 km
Let the average speed =xkm/hr
Distance travelled =90km
the average speed during this distance =(x+10)km/hr
DS=t
Total time taken =3hr
752+90x+10=3
=75(x+10)+90xx(x=10)=3
165x+750=3x2+30
=> 3x2±135x−750=0
=> x2−45x−250=0
(x−50)(x+5)=0
x=−5 is not admissible.
Hence =50km/hr
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