a bus traveling at 15m/s acceleration uniformly at 4m/s² what is the distance covered in 10secs
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Answer:
Initial velocity u=15m/s
Acceleration a= 4 m/s2
Time t=10 s
Final velocity (v):
v=u+at
=15+4x10
v=55 m/s
Distance (s):
v^2-u^2=2as
s=(v^2-u^2)/(2a)
=(55^2 - 15^2)/(2x4)
=350 m
Distance covered = 350 m
Explanation:
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