Physics, asked by kadrizion, 6 months ago

a bus traveling at 15m/s acceleration uniformly at 4m/s² what is the distance covered in 10secs

Answers

Answered by LEGEND778
0

Answer:

Initial velocity u=15m/s

Acceleration a= 4 m/s2

Time t=10 s

Final velocity (v):

v=u+at

=15+4x10

v=55 m/s

Distance (s):

v^2-u^2=2as

s=(v^2-u^2)/(2a)

=(55^2 - 15^2)/(2x4)

=350 m

Distance covered = 350 m

Explanation:

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