A bus traveling at 36 m /h acceleration for 5 sec. to attain a velocity of 54 km/h . Find its acceleration.
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5
QUESTION:
A bus traveling at 36 m /h acceleration for 5 sec. to attain a velocity of 54 km/h . Find its acceleration.
ANSWER:
SOLUTION:
Equation
v = u + at
36 km /h = 36*1000 /( 60*60) = 10 m/s
54 km /h = 56*1000/(60*60) = 15 m/s
substitute
15 m/s = 10 m/s + a* 5 s
a*5s = 5m/s
a = 5m/s / 5 s
a = 1 m/s².
IMPORTANT FORMULA:
⏩v=u+at
⏩s=ut+12at2
⏩s=vt−12at2
⏩s=12(u+v)
Answered by
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Given the bus is travelling at 36 m/h
= (36 / 60 x 60) m/s
= 36 / 3600 m/s = 1/100 m/s = 0.01 m/s
Given time = 5s
Given velocity = 54 km/h
➥ 54 x 1000 / 3600
➥ 54 x 5/18
➥ 3 x 5 = 15 m/s
✏ We know that : v = u + at
➯ 15 = 0.01 + a x 5
➯ 15 - 0.01 = 5a
➯ 14. 99 = 5a
∴ a = 14.99 / 5 = 2.998 m/s²
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