Question

a bus travelling at 15m/s accelerate uniformly at 5ms–2 what is the distance covered in 10seconds

Answer 1

$<b><font color = "yellow">Heya mate. (^_-). Solution below.</font color>$
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$<u><font color = "orange">★ Given -</font color></u>$

Initial velocity (u) = 15 m/s

Acceleration (a) = 5 m/s²

Time taken (t) = 10 second



$<u><font color = "blue">★ To find -</font color></u>$

Distance covered (s) = ?



★ From the second equation of motion, we know that,

s = ut + ½at²



★ Then, the distance covered, s

= ut + ½at²

= (15 × 10) + (½ × 5 × (10)²)

= (150) + (½ × 5 × 100)

= (150) + (5 × 50)

= (150) + (250)

= 400



•°• The distance covered by bus = 400 m.
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$<font color ="red"><marquee>Thank you..$