A bus travelling at 20 m/s is subjected to steady retardation of 5m/s.how long will it take to come at rest
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Answered by
2
intitial velocity (u) = 20m/s
final velocity (v) = 0 (as the body comes to rest)
acceleration = -5m/s^2
let time = t
using the formula of acceleration
a= (v-u)/t
-5= (0-20)/t
-5t = -20
t = 4
so, the time taken by the body to come at rest is 4s.
final velocity (v) = 0 (as the body comes to rest)
acceleration = -5m/s^2
let time = t
using the formula of acceleration
a= (v-u)/t
-5= (0-20)/t
-5t = -20
t = 4
so, the time taken by the body to come at rest is 4s.
Answered by
1
v^2 - u^2 =2as
Putting the values we get
S=40m
Putting the values we get
S=40m
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