a bus travelling at 20m/s is subjected to a stesd deacceleration of 5m/s square,how long will it tahe to come to rest.
Answers
Answered by
1
speed=20m/s
deacceleration=5m/s^2
d= speed/time
time=20(m/s)/5(m/s*s)
time=4s
deacceleration=5m/s^2
d= speed/time
time=20(m/s)/5(m/s*s)
time=4s
Anshbeniwal:
but de acceleration is 5m^2
which you have written in time
why?
can you explain me
its nt m^2 its m/second suare
that means seconds unit is square nt metre
ok
thqnkyou
i edited in solution omce check
if u have still doubt let me know
Similar questions