Question

A bus travelling at 36 km/h accelerates uniformly for 5 seconds to attain a velocity of 54 km/h find its acceleration.​

Answer 1

Explanation:

T= 5s,a=?,u=36km/h --> 36×5/18=10ms‐¹,v=54km/h

54×5/18=15ms‐¹

a=(v-u)/t

a=(15-10)/5

a=5/5

a=1 ms‐²

Answer 2

The acceleration is 1 m/s².

Given - Initial and final Velocity and time

Find - Acceleration

Solution - The acceleration can be calculated through equation of motion. The equation of motion to be used in this question is : v = u + at. In this equation, v is final velocity, u is initial velocity, a is acceleration and t is time.

Firstly converting velocity into m/s. For this, we will simple multiply the values with 5/18.

So, initial velocity = 36 km/hr

Initial velocity = 36*5/18

Initial velocity = 10 m/s

Final velocity = 54 km/hr

Final velocity = 54*5/18

Final velocity = 15 m/s

Keep the values in equation of motion.

15 = 10 + a*5

a*5 = 15 - 10

Performing subtraction

a*5 = 5

a = 5/5

Performing division

a = 1 m/s²

Hence, the acceleration is 1 m/s².

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