A bus travelling at 42 km/hrs covers a distance in 5 hrs . How much time would it save if it increased its speed by 8 km/hrs.........please help me to solve this you may get 50 points.....this question is from speed,time,and distance...
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0
Answer:
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Step-by-step explanation:
Given:1) Speed=42km/hr. 2) Time=5hr
By formula :
Speed=distance/time………(1)
Distance=Speed*time
So,
Distance=42km/hr*5hr=210 km
Therefore,time required when speed is increased by 8 km/hr:
Time =Distance/speed….from(1)
Increased speed=(42+8)km/hr=50km/hr
Time=210/50
Time=4.2hr
Time required when speed is increased by 8km/hr is 4.2 hr.
Answered by
2
Answer:
The bus travelling at 42 km/hrs
The bus covers a distance in 5 hrs
So the distance
= Speed × Time
= 42 × 5 km
= 210 km
Now if it increased its speed by 8 km/hrs
Then new speed = (42+8) = 50 km/ h
So the required time
= Distance / Speed
= 210/50 h
= 21/5 h
= 4 hr 12 min
So the time would be saved
= 5 hr - 4 hr 12 min
= 48 min
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