A BUS TRAVELLING AT 42KM/H COVERS A DISTANCE IN 5H.HOW MUCH TIME WOULD IT SAVE IF IT INCREASED ITS SPEED BY 8KM/H? STEP BY STEP
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Answered by
80
distance covered in 5hrs = 42×5 = 210km
if speed is increased by 8km/h , new speed = 42+8 = 50 km/h
new time = 210/50 = 4.2 hours
time saved = 5 - 4.2 = 0.8 hours
0.8 hours = 0.8 × 60 = 48 minutes
Time saved = 48 minutes
if speed is increased by 8km/h , new speed = 42+8 = 50 km/h
new time = 210/50 = 4.2 hours
time saved = 5 - 4.2 = 0.8 hours
0.8 hours = 0.8 × 60 = 48 minutes
Time saved = 48 minutes
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Answered by
21
Answer:
Step-by-step explanation:
the distance would be same so
Speed =distance /time
42*5=50x
X = the time taken
210=50x
X=210/50
X=4.2
you don't have any
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