Question

a bus travelling in a straight line with 126 km per hour comes to rest after 200 m what is its acceleration

Answer 1

Initial velocity [u] = 126 km/hr = 126 * 5/18 m/sec  
                                               = 35 m/sec     
Final velocity [v] = 0 m/sec
Distance traveled before coming into rest [s] = 200 m
Acceleration [a] = ?

According to equation of motion =
v^2 - u^2 = 2as
SO, a = v^2 - u^2 / 2s
          = 0^2 - 35^2 / 2*200
          = 0 - 1225 / 400
          = - 3.0625 
THEREFORE, retardation is 3.0625.. { or } acceleration is -3.0625...

I HOPE THIS ANSWER WAS HELPFUL TO YOU......

THANK YOU!!!!!!!