A bus travelling the first one third distance at a speed of 10 km/h, the next one third at 20 km/h and the last one-third at 60 km/h. the average speed of the bus is
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288
Let total distance be x
It covered
x/3 at 10
x/3 at 20
x/3 at 60
Times taken respectively are { d / t }
x / 30
x / 60
x / 180 respectively
total time = x/30 + x /60 + x/180
= 10x / 180
= x / 18
Average speed of bus (avg s )
= total distance / total time
avg s = x / {x/18}
avg s = 18 km / h
ANSWER = 18 km/hr
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It covered
x/3 at 10
x/3 at 20
x/3 at 60
Times taken respectively are { d / t }
x / 30
x / 60
x / 180 respectively
total time = x/30 + x /60 + x/180
= 10x / 180
= x / 18
Average speed of bus (avg s )
= total distance / total time
avg s = x / {x/18}
avg s = 18 km / h
ANSWER = 18 km/hr
HOPE IT HELPS :):):):)
MARK AS BRAINLIEST
Answered by
58
Let total distance be x
It covered
x/3 at 10
x/3 at 20
x/3 at 60
Times taken respectively are { d / t }
x / 30
x / 60
x / 180 respectively
total time = x/30 + x /60 + x/180
= 10x / 180
= x / 18
Average speed of bus (avg s )
= total distance / total time
avg s = x / {x/18}
avg s = 18 km / h
ANSWER = 18 km/hr
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