A bus travelling the first one third distance at a speed of 10 km/hr ,the next one fourth distance at 20 km/hr and the remaining at 40 km/hr.The average speed of the bus is about ?
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If total distance is S then
Average speed = Total distance / Time
= S / (t1 + t2)
= S / [(S/(3 * 10)) + (S/(4 * 20)) + (5S/(12 * 40))]
...….....[∵ Time = Distance / Speed]
= 1 / (1/30 + 1/80 + 5/480)
= 17.7 kmph
In two significant figures average speed will be 18 kmph
Average speed = Total distance / Time
= S / (t1 + t2)
= S / [(S/(3 * 10)) + (S/(4 * 20)) + (5S/(12 * 40))]
...….....[∵ Time = Distance / Speed]
= 1 / (1/30 + 1/80 + 5/480)
= 17.7 kmph
In two significant figures average speed will be 18 kmph
Anonymous:
are u sure about the ans ?
Edited.
In the book the answer is given as
18 km/hr
Thanks :)
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