A bus travelling the first one-third distance at a speed of 10kmph the next one-fourth at 20kmph and the next remaining at 40kmph .what is the average speed of the bus
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0
Answer:
total distance cover in total time,,,
<v>=s/t
40×3600/20×3600
= 2 m/s
Answered by
3
Explanation:
as distance is same then
avg speed = 3×v1×v2×v3/v1v2+ v2v3+v3v1
v1 = 10kmph v2 = 20kmph v3 = 60kmph
avg speed = 3 ×10×20×60/10(20) + 20(60)+60(10)
= 36000/200+1200+600
= 36000/2000
= 18 kmph
therefore , avg speed = 18 kmph
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