Question

A bus travels 50% faster than a car. Both start moving at the same time from station p and reach station q at the same time. The stations are 100 km apart. If on the way the bus stops at the bus stop for 10 minutes, find the speed of the car.

Answer 1

Answer:

100÷x-100÷1.5x=10

.5/1.5x=.1

1/3x=1/10

X=10×60/3=200

speed of the car=200Km/hr

Answer 2

The speed of the car is 200km/hr.

Given:-

Distance between the bus stops = 100km

Time taken to stop = 10 minutes

Speed of bus = 50% faster Speed of car

To Find:-

The speed of the car.

Solution:-

You can find the speed of the car by using the following procedure, which includes.

As

Distance between the bus stops = 100km

Time taken to stop = 10 minutes

Speed of bus = 50% faster Speed of car

Let we assume the speed of car be 'v'

then, the speed of bus = 3v/2

According to formula,

$speed = \frac{distance}{time}$

$time = \frac{distance}{speed}$

$\frac{100}{v} - \frac{100}{ \frac{3v}{2} } = \frac{10}{60}$

$\frac{100}{v} - \frac{200}{3v} = \frac{1}{6}$

$\frac{300 - 200}{3v} = \frac{1}{6}$

$\frac{100}{3v} = \frac{1}{6}$

$3v = 600$

$v = \frac{600}{3}$

v = 200km/hr

Hence, The speed of the car is 200km/hr.

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