Question

A bus travels a distance of 100 km with a speed of 50km/h and returns with a speed of 30 km/h.calculate the average speed for the entire journey​

Answer 1

A bus travels a distance of 100 km with a speed of 50 km/h.

Given that, distance (d) = 100 km and speed of bus (s) = 50 km/hr.

Also given that, the bus returns with a speed of 30 km/h.

Still the distance is same i.e. 100 km

Assume that the bus starts from point A to B (A→B) and covers a distance of 100 km with a speed of 50 km/hr.

Now, the bus returns to it's actual point A (from B to A point) with a speed of 30 km/hr.

So, the total distance = (A→B + B←A) 100 + 100 = 200 km

We know that,

Average velocity is defined as total distance covered by the total time taken.

Also time = distance/speed

According to question,

→ 200/(100/50 + 100/30)

→ 200/(2 + 3.33)

→ 200/(5.33)

→ 37.52 km/hr

Answer 2

$</p><p>\tt{\blue{\huge{Hello!!! }}}$

$</p><p>\tt{\red{Given \: - }}$

A bus travels a distance of 100 km with a speed of 50km/h and returns with a speed of 30 km/hr.

$</p><p>\tt{\purple{Average \: Speed \: - }}$

$\tt{ \orange{ \implies{ \: \dfrac{200}{ \dfrac{100}{50} + \dfrac{100}{30} }= 37.52\: km/hr }}}........(A)$