A bus travels at a certain speed for a distance of 150 km and then travels a distance of 180 km at an average speed of 10km/h more than the first speed
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Let the speed of bus be x
Speed of bus at 180km=x+10
Average of both =x+x+10/2=x
2x+10=x*2
10=2x-2x
10kmph was the speed of bus at beginning.
Speed of bus at 180km=x+10
Average of both =x+x+10/2=x
2x+10=x*2
10=2x-2x
10kmph was the speed of bus at beginning.
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