Question

A bus travels at rate of 25 km/h for 4 minutes, then at 50km/h for 8 min , and finally at 20km/h for 2 min. Find the total distance covered in km and the average speed for complete trip in my/s. I will give you 100 points please answer me please​

Answer 1

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v₁ = 25 km/h

t₁ = 4 minutes = (4/60) h

d₁ = distance traveled in 4 min = v₁ t₁ = 25 (4/60) = 1.67 km

v₂ = 50 km/h

t₂ = 8 minutes = (8/60) h

d₂ = distance traveled in 8 min = v₂ t₂ = 50 (8/60) = 6.67 km

v₃ = 20 km/h

t₃ = 2 minutes = (2/60) h

d₃ = distance traveled in 2 min = v₃ t₃ = 20 (2/60) = 0.67 km

d = total distance

Total distance is given as

d = d₁ + d₂ + d₃

d = 1.67 + 6.67 + 0.67

d = 9.01 km

t = total time = t₁ + t₂ + t₃ = 4 + 8 + 2 = 14 min = (14/60) hour

average speed is given as

v = d/t

v = 9.01/(14/60)

v = 38.6 km/h

v = 38.6 (5/18) m/s

v = 10.7 m/s

Answer 2

Answer:

bus travelled 8.9 km

average speed 0.9 m/s

hope it will help mark me brainliest