Question

a bus travels at the rate of 24km/hr leaves imphal to phungyar at 7am. at what distance will it meet a jeep which leavesphungyar to imphal at 7.20am and travels one third faster then bus, the distance imphal to phungyar being 97km.

Answer 1

speed of the car =24×4/3=32kmph
the distance left to travel by bus =97-8=89km

Answer 2

Answer:

The bus and jeep meet at 8:20 after covering 32 km.

Step-by-step explanation:

Given that

Speed of bus = 24 kph (kilometer per hour)

Speed of a jeep = Speed of bus + one third speed of bus

Speed of a jeep = 24 + $\frac{24}{3}$

Speed of a jeep = 24 + 8 = 32 kph

Now at 8:20 the bus will have covered

Distance covered by bus from 7:00 to 8:20 am = vt = 24 * 1.33 = 32 km

Now at 8:20 the jeep will have covered

Distance covered by jeep from 7:20 to 8:20 am = vt = 32 * 1 = 32 km

So, both the bus and jeep meet at 8:20 after covering 32 km