a bus travels first 100 km with the speed of 50km/hr and next 80km in the speed of 40km/hr calculate the average speed of the bus
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Answered by
37
HEY BUDDY..!!
HERE'S THE ANSWER..
_______________________________
♠️ Average speed of a vehicle is defined as ratio of total distance traveled to the total time taken , i.e
✔️ Avg. Speed = ( D1 + D2 ) / t1 + t2
▶️ First we'll time 1 and time 2
=> Speed = Distance / time
=> time 1 = Distance / Speed
=> time 1 = 100 / 50
=> time 1 ( t1 ) = 2 Hour
✔️ time 2 = Distance / Speed
=> time 2 = 80 / 40
=> time 2 ( t2 ) = 2 Hour
♠️Avg. Speed = ( D1 + D2 ) / t1 + t2
=> Avg. Speed = ( 100 + 80 ) / 2 + 2
=> Avg. Speed = ( 180 ) / 4
=> Avg. Speed = 45 Km / h
HOPE HELPED..
JAI HIND..
:-)
HERE'S THE ANSWER..
_______________________________
♠️ Average speed of a vehicle is defined as ratio of total distance traveled to the total time taken , i.e
✔️ Avg. Speed = ( D1 + D2 ) / t1 + t2
▶️ First we'll time 1 and time 2
=> Speed = Distance / time
=> time 1 = Distance / Speed
=> time 1 = 100 / 50
=> time 1 ( t1 ) = 2 Hour
✔️ time 2 = Distance / Speed
=> time 2 = 80 / 40
=> time 2 ( t2 ) = 2 Hour
♠️Avg. Speed = ( D1 + D2 ) / t1 + t2
=> Avg. Speed = ( 100 + 80 ) / 2 + 2
=> Avg. Speed = ( 180 ) / 4
=> Avg. Speed = 45 Km / h
HOPE HELPED..
JAI HIND..
:-)
Answered by
22
t1 = d1 / s1
t1 = 100 / 50
t1 = 2 h
t2 = d1 / s1
t2 = 80 / 40
t2 = 2 h
avg speed = ( 100 + 80 ) / 2 + 2
= 180 / 4
= 45 km/h
t1 = 100 / 50
t1 = 2 h
t2 = d1 / s1
t2 = 80 / 40
t2 = 2 h
avg speed = ( 100 + 80 ) / 2 + 2
= 180 / 4
= 45 km/h
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