a bus travels first 100 kmwith the speed of 50 km h-1and the next 80 km with the speed of 40 km h-1 calculate the average speed of the bus
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avg speed=2xy/x+y
where X and y are speeds
substituting the speeds
avg. speed= 2*50*40/50+40
= 100*40/90
4000/90
=400/9
=44.4kmph(approx)
where X and y are speeds
substituting the speeds
avg. speed= 2*50*40/50+40
= 100*40/90
4000/90
=400/9
=44.4kmph(approx)
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