Question

A bus travels half a distance at uniform speed 6m per sec
and the next half at uniform speed 4m per sec
.The average speed (m per sec) for the full journey is
(a) 5 (b)2.4 (c) 4.8 (d) √26

Answer 1

Answer:

(c) 4.8m/s

Explanation:

by using the formula, 2v1v2/v1+v2

2*6*4/6+4=48/10=4.8m/s

Answer 2

Answer:

Explanation:

Average speed = total diatance/total time

v = d/t

t1 = d1/v1 = d1/4

t2 = d2/v2 = d2/6

Total distance D = d1 + d2

Total time = d1/4 + d2/6

But d1= d2 = D/2

Total time = d1/4 + d1/6 = 5d1/12

Substitute d1 = D/2

Total time = 5(D/2)/12 = 5D/24

Now to get the average speed

Average speed =total distance/total time

Average speed= D ÷ 5D/24

Average speed = D x 24/5D = 4.8m/s

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