A bus travels half a distance at uniform speed 6m/s
and the next half at uniform speed 4m/s
.The
average speed
for the full journey is
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Answer
Average speed = total diatance/total time
v = d/t
t1 = d1/v1 = d1/4
t2 = d2/v2 = d2/6
Total distance D = d1 + d2
Total time = d1/4 + d2/6
But d1= d2 = D/2
Total time = d1/4 + d1/6 = 5d1/12
Substitute d1 = D/2
Total time = 5(D/2)/12 = 5D/24
Now to get the average speed
Average speed =total distance/total time
Average speed= D ÷ 5D/24
Average speed = D x 24/5D = 4.8m/s
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Average speed = total diatance/total time
v = d/t
t1 = d1/v1 = d1/4
t2 = d2/v2 = d2/6
Total distance D = d1 + d2
Total time = d1/4 + d2/6
But d1= d2 = D/2
Total time = d1/4 + d1/6 = 5d1/12
Substitute d1 = D/2
Total time = 5(D/2)/12 = 5D/24
Now to get the average speed
Average speed =total distance/total time
Average speed= D ÷ 5D/24
Average speed = D x 24/5D = 4.8m/s
Mark as Brainlist
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