A bus travels one-third of distance with a velocity of 12km/h and remaining distance with 20km/h. Find its average speed
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Let the distance be X.
1 / 3 x he covers using 12 km / h
Remaining = 2 / 3 km which he covers using 20 km / h
Lets take the distance x to be 1 then :
Time for the first portion will be:
T = Distance / speed
1/3 × 1/12 = 1/36 hrs
Second portion:
2 / 3 × 1/20 = 1 / 30 hrs
Average speed = total distance / total time
Total time = (1/36) + (1/30) = 0.3611 hrs
Average speed :
1 ÷ 0.3611
= 3 km / h (approx)
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