Question

a bus travels one third of the distance with a speed of 4m/s . if the average speed of object is 6m/s then calculate the speed of a body in second half
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Answer 1

Explanation:

distance = speed x time

For the first half of the distance, the speed was 4 m/s.

d1=4t1

For the second half of the distance, the speed was 6 m/s.

d2=6t2

Since each distance was equal to half of the total, we know that:

d1=d2

Which means that:

4t1=6t2

Rearranging we get:

t1=64t2

t1=1.5t2

So the first portion of the trip took 1.5 times as long as the second portion. Therefore the entire trip took:

ttotal=t2+1.5t2=2.5t2

And the total distance is:

dtotal=d1+d2=4(1.5t2)+6t2=12t2

Now that we know the total distance and the total time, we can get the average speed:

s¯=12t22.5t2=4.8m/s

Hope this will help you