A bus travels with uniform velocity of 20 m/s for 5 s. The brakes are then applied and the bus is uniformly retarded and comes to rest in further 8 s. Draw a graph of velocity – time and find A. The distance travelled in first 5 s. B. The distance travelled after the brakes are applied. C. The total distance travelled. D. The acceleration during the first 5 s and last 8 s.
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A ) distance covered in 5s=20×5
=100 meters
B) distance covered after applying breakes =20×8
=160 meters
C) total distance travelled = 100+160
= 260 meters
D) Acceleration = final velocity - starting velocity /time
starting velocity=20m/s
final velocity = According to the problem the car comes to rest in 8 second so the final velocity should be = 0
time =5 seconds
acceleration during Frist 5 seconds= 0-20/5=-4
so the acceleration is -4
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and now acceleration in 8 second
=0-20/8
acceleration = -2.5
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