A bus was moving with a speed of 54 km/h. On applying brakes , it stopped in 8s . Calculate the acceleration and the distance travelled before stopping
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Answered by
12
u=54km/h
=15m/s
v=0
t=8s
a=v-u/t
=0-15/8
=-15/8
=-1.875m s -2
=15m/s
v=0
t=8s
a=v-u/t
=0-15/8
=-15/8
=-1.875m s -2
Answered by
7
distance= speed × time
d=54 km/h= 15m/s
d=15 × 8=120m
acceleration=(final speed - intial speed) / time
a=15 - 0 / 8
=1.875m/s
d=54 km/h= 15m/s
d=15 × 8=120m
acceleration=(final speed - intial speed) / time
a=15 - 0 / 8
=1.875m/s
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