.A bus was moving with a speed of 54 km/h. On applying brakes,it stopped in 8 seconds. Calculate the speed acquired and the distance travelled in this time.
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54 kmph = 54×5/18 m/s = 15 m/s
acceleration a = (v-u)/t = (0-15)/8 = - 15/8 m/s^2
distance travelled = (v^2-u^2)/2a = -(0-225)/(30/8) = 60 m
the speed acquired finally is zero
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acceleration a = (v-u)/t = (0-15)/8 = - 15/8 m/s^2
distance travelled = (v^2-u^2)/2a = -(0-225)/(30/8) = 60 m
the speed acquired finally is zero
hope it helped
follow me for more help
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