Physics, asked by priyadarshini0808, 8 months ago

A bus was moving with a speed of 54km/hr. On applying breaks it stopped in 8 seconds. calculate the acceleration

Answers

Answered by yogeshparashar452
4

Explanation:

According to the question,

Initial Velocity of bus = 54 km/h = 54 X 5/18 = 15 m/s

Final Velocity of bus = 0 (As brakes are applied and bus gradually comes to rest)

Time taken to reach the Final Velocity = 8 seconds

Acceleration = v - u / t

a = 0 - 15 / 8

Retardation =  - 1.875 m/s²

For calculating Distance,  S = u X t + 1/2 at²

S = ( 15 X 8 ) + 1/2 X -1.875 X 8²

S = 120 + ( -120/2 )

S = 120 + (- 60)

S = 120 - 60

Distance travelled by the bus before stopping = 60 metres

Answered by s21923
0

Answer:

Answer: Initial Speed (u)= 54 km /hr = 54 *1000 m / 3600 s = 54*5/18 = 15 m/s ( 1km = 1000 m and 1hr = 60 mins = 60*60 seconds = 3600 seconds)

Explanation:

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