A bus was moving with a speed pf 54 km/h on applying breaks it stopped in 8 sec and calculate the acceleration
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hey your ans is here
__________
given:-
initial velocity=54km/h-------m/sec
54×5/18=15 m/sec
initial velocity(u)=15
final velocity(v)=0 ( as the brakes are applied after )
time(t)=8 sec
acceleration(a)=v-u/t
a=0-15/8
a=-15/8
a=-1.8 m/sec2
retardation =1.8m/sec2
as the acceleration in negative that means the speed of body is decreasing and it is been retarded
___________
__________
given:-
initial velocity=54km/h-------m/sec
54×5/18=15 m/sec
initial velocity(u)=15
final velocity(v)=0 ( as the brakes are applied after )
time(t)=8 sec
acceleration(a)=v-u/t
a=0-15/8
a=-15/8
a=-1.8 m/sec2
retardation =1.8m/sec2
as the acceleration in negative that means the speed of body is decreasing and it is been retarded
___________
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