Question

A bus was moving with a speed qof 54 km/h on applying brakes it stopped in 8 second calculate the acceleration

Answer 1

$u = 54kmhr \\ \: \: \: \: = 54 \times \frac{5}{18} = 15ms \\ t = 8s \\ v = 0 \\ a = \frac{v - u}{t} \\ a = \frac{0 - 15}{8} \\ a = \frac{ - 15}{8}$

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Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

Information which is given,

u (Initial Velocity) = 54 km/h

u = 54 × 5/18

u = 15 m/s

Also,

v (Final Velocity) = 0 (Because bus stops by applying breaks)

t (Time taken) = 8 seconds.

Now,

Using 1st Equation of Motion,

v = u + at

⇒ 0 = 15 + a × 8

⇒ 0 = 15 + 8a

⇒ a = - 15/8

⇒ a = - 1.875 m/s²

Therefore,

Acceleration by bus = -1.875 m/s²