A bus was moving with a uniform speed of 54km/h.on applying brakes,it stoppedin 8s.find the acceleration and the distance travelled by the object before stopping
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u = 54 km/h = 15 m/s
v =0
t = 8 sec
as, v = u +at
⇒0 = 15 + a×8
⇒8a = -15
⇒a = -1.875 m/s²
also, v² - u² = 2as
⇒(0)² - (15)² = 2×(-1.875)×s
⇒s = 60 m
v =0
t = 8 sec
as, v = u +at
⇒0 = 15 + a×8
⇒8a = -15
⇒a = -1.875 m/s²
also, v² - u² = 2as
⇒(0)² - (15)² = 2×(-1.875)×s
⇒s = 60 m
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