Question

A bus which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s² over a distance of 340 m. How fast is it going after that acceleration? ​

Answer 1

Given :-

Initial velocity of the bus = 15m/s

Acceleration of the bus, a = 6.5m/s²

Distance covered, s = 340m

To Find :-

Final velocity of the bus

Solution :-

As we are provided with initial Velocity (u) accerlation and distance covered we can use 3rd equation of motion so,

By using 3rd equation of motion .i.e.,

➠ v² = u² +2as

here,

v denotes final velocity, u denotes initial Velocity, a denotes accerlation and s denotes distance covered

now, substituting all the given values,

➠ v² = 15² + (2)(6.5)(340)

➠ v² = 225 + 4420

➠ v² = 4645

➠ v = √4645

➠ v = 68.15 m/s

thus, the final velocity of the bus is 68.15 m/s.

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