a bus which travels at the rate of 24km/hr leaves Imphal for phungyar at 7am. at what distance from Imphal will it meet a jeep which leaves phungyar for Imphal at 7:20am and travels one third faster than the bus, the distance from Imphal to phungyar being 97km.
Answers
Answer:
The bus and jeep meet at 8:20 after covering 32 km.
Step-by-step explanation:
Given that
Speed of bus = 24 kph (kilometer per hour)
Speed of a jeep = Speed of bus + one third speed of bus
Speed of a jeep = 24 + \frac{24}{3}
Speed of a jeep = 24 + 8 = 32 kph
Now at 8:20 the bus will have covered
Distance covered by bus from 7:00 to 8:20 am = vt = 24 * 1.33 = 32 km
Now at 8:20 the jeep will have covered
Distance covered by jeep from 7:20 to 8:20 am = vt = 32 * 1 = 32 km
So, both the bus and jeep meet at 8:20 after covering 32 km
Answer:
46⅐km from imphal.
Step-by-step explanation:
speed of bus = 24km
speed of jeep = (⅓×24)+24=32km
distance of bus from 7a.m. to 7:20a.m.
=⅓×24=8km. [20mins=⅓hr]
remaining distance=97-8=89km.
from 7:20a.m.,
time to meet= 89/(24+32)=89/56hrs
distance from imphal
= [(24 × 89/56)+8]
= (267/7 +8)
= (267+56)/7
= 323/7
= 46⅐km.