Question

A business man has 600000 at his disposal and wants to purchase cows and buffaloes
to take up a business. The cost price of a cow is 20,000 and that of a buffalo is
60000. The man can store fodder for the live stock to the extent of 40 quintals per
week. A cow gives 10 litres of milk and buffalo gives 20 litres of milk per day. Profit per
litre of milk of cow is 5 and per litre of the milk of a buffalo is 7. If the consumption
of fodder per cow is 1 quintal and per buffalo is 2 quintals a week, formulate the problem
as a linear programming problem to find the number of live stock of each kind the man
has to purchase so as to get maximum profit (assuming that he can sell all the quantity of
milk, he gets from the livestock)

Answer 1

Answer:

20000x+60000y = 40

60000x-70000y = 20

use elimination method to solve this