Math, asked by GaganTripathi6958, 10 months ago

A business tycoon left for a foreign visit on 12 August 2008 and came back on 5 September 2010 how long did he remain abroad

Answers

Answered by amitnrw
4

755 Days  business tycoon remain abroad if he left for a foreign visit on 12 August 2008 and came back on 5 September 2010

Step-by-step explanation:

A business tycoon left for a foreign visit on 12 August 2008 and came back on 5 September 2010

2009 & 2010 are not leap year

so  365 * 2  = 730 Days

Now to find Days from 12 Aug 2010 to 5 Sep 2100

20 Days in Aug

5 Days in Sep

Total number of Days stayed in Abroad =  730 + 20 + 5

= 755 Days

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Answered by XxItzhearthakkerxX
14

Answer:

above id is correct answer sorry for spamming XD XD

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