Math, asked by shailendrasingh08, 3 months ago

a business tycoon left for a foreign visit on 12th august, 2008 and come back on 5th September 2010 how long did he remain abroad​

Answers

Answered by ryqa2508
0

Answer:

571 days

or 1 year and 206 days

Step-by-step explanation:

12th August - 31st August = 19 days

2009 = 365 days

January, March, May, July, August = 31 days * 5

total = 155 days

February = 28 days

and 4 days in September

Thus,

19 + 365 + 155 + 28 + 4 = 571 days

*5th September 2010 doesn't include because the tycoon come back on that day

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