a business uses two 3kw fires for an average of 20 hours each per week,and six 150watt lights for 30 hours each per week. If the cost of electricity is 7p per unit then determine the weekly cost of electricity and to the business
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Answered by
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Two lamps of each = 3kw×2=6kw
time used every week = 20h
electrical energy consumed = power×time = 20×6= 120kwh= 0.12unit
six bulb= 150×6 = 900kw
time= 30h
power =30×900= 27000kwh =27 unit
Total electrical energy consumed = 27+0.12=27.12unit
1 unit=7p
27.12unit = 27.12 ×7= 189.84 p
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Answer:1.029p
Explanation:Two fire sources each of=3kw
Now total power of two sources=2×3kw=6kw
Time taken=20 hrs
Therefore,energy=P×T=6×20
=120kwh=0.12 units
Now,total power dissipated by 6 lights=6×150=900 W=0.9 kw
Time taken=30 hrs
Energy consumed=P×T=30×0.9=27kwh
=0.027 unit
Total energy consumed=0.027+0.12=0.147 units
1 unit=7p
So,cost=7×0.147
=1.029p
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