A businessman bought 1,000 eggs. Of those, 90 eggs lay. The remaining eggs cost $9.60 per dozen It sold for a loss of 12%. Decide how much money the trader bought the eggs for ?
Answers
Answer: $ 9100/11
Step-by-step explanation: man bought 1000 eggs & lay 90
so remaining eggs, 1000 - 90 = 910
now, selling price of 12 eggs (a dozen) = 9.60 dollar
S.P of 1 egg = $9.60 ÷ 12 = 80 cents
S.P of remaining 910 eggs = $910 × 80 cents = 728.00 dollar
[now we can solve with two different methods]...
Let, the cost price of 1000 eggs = x
when C.P is x, loss of 12% = C.P. × loss% ⇒x × 12% ⇒12x/100 = 3x/25 (reducing the fraction to lowest by extracting and cancelling out 4)
we know, C.P - loss = S.P
so, x - 3x/25= 728
⇒(25x-3x)/25 = 728
⇒22x/25 = 728 ⇒22x = 728 × 25
⇒x = (728 × 25)/22 ⇒x = 18200/22
⇒x = 9100/11 dollar
Alternative:
loss of 12% means
when, Cost Price = 100, loss = 12
So, Selling Price = C.P - loss ⇒100-12 = 88
Now,
for Selling Price 88, Cost Price = 100
for Selling Price 1, C.P = 100/88
for Selling Price 728, Cost Price will be = 728 × 100/88 = 9100/11
Step-by-step explanation:
ANSWER IS 9100/11 DOLLAR