a businessman bought some otems for rs. 7500 . he kept 5 items for himself & sold remaining items at a profit of 25 rs. per item from the amount received in his deal he could buy 6 more items find the original price of each item.
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let the total number of items be x.
let the cost of one item be Rs. y.
total cost of items = Rs. 7500
therefore,
x × y = 7500
=> x = 7500/y
items remaining after keeping 5 items for himself = x-5
therefore,
(x-5) × 25 = 6y
{(7500/y) - 5} × 25 = 6y
SOLVE THIS AND YOU WILL GET YOUR ANSWER.
let the cost of one item be Rs. y.
total cost of items = Rs. 7500
therefore,
x × y = 7500
=> x = 7500/y
items remaining after keeping 5 items for himself = x-5
therefore,
(x-5) × 25 = 6y
{(7500/y) - 5} × 25 = 6y
SOLVE THIS AND YOU WILL GET YOUR ANSWER.
Answered by
0
Let me continue to solve the equation that SmartSmarth set.
[tex]( \frac{7500}{y} -5) 25 = 6y [/tex]
Multiply y to both side
(7500-5y)25 = 6y²
187500-125y = 6y²
6y²+125y-187500=0
Using the quadratic formula to solve it and reject the negative root, you will get
as the original price
[tex]( \frac{7500}{y} -5) 25 = 6y [/tex]
Multiply y to both side
(7500-5y)25 = 6y²
187500-125y = 6y²
6y²+125y-187500=0
Using the quadratic formula to solve it and reject the negative root, you will get
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