Question

A businessman bought two cars for Rs.800000. He sold one car at a profit of 30% and the other at a loss of
10%. If the S.P. of cars is same, then the cost price of each car is​

Answer 1

Answer:

472727.3 and 327272.7

Answer 2

The cost price of two cars are Rs. 472727.3 and Rs. 327272.7

Given :

• A businessman bought two cars for Rs. 800000

• He sold one car at a profit of 30% and the other at a loss of 10%

• The SP of both books is same

To find :

The cost price of two cars

Solution :

Step 1 of 2 :

Form the equation to calculate cost price of two cars

The businessman bought two cars for Rs. 800000

Let cost price of two cars are Rs. C and Rs. (800000 - C) respectively

The businessman sold one car at a profit of 30% and the other at a loss of 10%

So by the given condition

$\displaystyle \sf C \times \frac{130}{100} = (800000 - C) \times \frac{90}{100}$

Step 2 of 2 :

Calculate cost price of two books

$\displaystyle \sf C \times \frac{130}{100} = (800000 - C) \times \frac{90}{100}$

$\displaystyle \sf{ \implies } C \times 130 = (800000 - C) \times 90$

$\displaystyle \sf{ \implies } 130C = 72000000 - 90C$

$\displaystyle \sf{ \implies } 130C + 90C = 72000000$

$\displaystyle \sf{ \implies } 220C = 72000000$

$\displaystyle \sf{ \implies } C = \frac{72000000}{220}$

$\displaystyle \sf{ \implies } C \approx 327272.7$

Cost price of 1st car

= Rs. C

= Rs. 327272.7

Cost price of 2nd car

= Rs. (800000 - C)

= Rs. (800000 - 327272.7)

= Rs. 472727.3

∴ The cost price of two books are Rs. 327272.7 and Rs. 472727.3

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