Math, asked by psayushuskp, 11 months ago

a businessman invited a principle of rupees 600000 he had a profit of 6% in the first year which road to 8% in the second year thereafter incurred a loss of 10% find the total profit of the shopkeeper after 3 years​

Answers

Answered by sarfraz38
2

Answer:

given ,

a business invited a priciple of rupees 6 lakh

profit in the 1st year= 6%

i.e 6/100*600000

=36000

now he has 636000

in the 2nd year he has a profit of 8 %

i.e 8/100*636000

=50880

now he has 686880

in the 3rd year he has a loss of 10%

i.e 10/100*636880

=63688

therefore amount left with him is 623192(his current balance)

Answered by scarlet02
0

Answer:

Rupees 24,000.

Step-by-step explanation:

Invested amount = 6,00,000 rupees

1st = 6% of 6,00,000 that is rupees 36,000. (which is profit).

2nd = 8% of 600000 that is rupees 48,000.

3rd = 10% of 6,00,000 that is rupees 60,000.(which is loss).

Overall Profit = 36,000 + 48,000 - 60,000 = rupees 24,000.

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