a businessman invited a principle of rupees 600000 he had a profit of 6% in the first year which road to 8% in the second year thereafter incurred a loss of 10% find the total profit of the shopkeeper after 3 years
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2
Answer:
given ,
a business invited a priciple of rupees 6 lakh
profit in the 1st year= 6%
i.e 6/100*600000
=36000
now he has 636000
in the 2nd year he has a profit of 8 %
i.e 8/100*636000
=50880
now he has 686880
in the 3rd year he has a loss of 10%
i.e 10/100*636880
=63688
therefore amount left with him is 623192(his current balance)
Answered by
0
Answer:
Rupees 24,000.
Step-by-step explanation:
Invested amount = 6,00,000 rupees
1st = 6% of 6,00,000 that is rupees 36,000. (which is profit).
2nd = 8% of 600000 that is rupees 48,000.
3rd = 10% of 6,00,000 that is rupees 60,000.(which is loss).
Overall Profit = 36,000 + 48,000 - 60,000 = rupees 24,000.
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