Question

A businessman purchased 160 radio sets and 140 clocks at a cost of 55,500. He sold the
radio set at 10% profit and clock at 4% loss. If he earned a total profit of 1,140, then find
out the purchase price of one radio set and one clock.
(Ans. 150, 225]​

Answer 1

Answer:

Step-by-step explanation:

Let the cost price (C.P) of A be Rs x

and that of B be Rs y 3

Total cost =Rs650  - [Given]

∴x+y=650

For A  

Profit =20%

Profit %=  

C.P

Profit

​  

×100

∴20=  

C.PofA

sellingpriceof(S.P)−C.PofA

​  

×100

∴  

5

1

​  

=  

x

S.P−x

​  

 

∴S.P. of A=  

5

6x

​  

 

For B  

Loss =25%

Loss%  

C.P

Loss

​  

×100

25=  

C.PofB

C.PofB−sellingprice(S.P)ofB

​  

×100

4

1

​  

=  

y

y−S.P

​  

 

4

y

​  

=y−S.P. of B  

∴ SP of B =  

4

3y

​  

 

But, according to the given concoction  

S.P of A=S.P of B  

5

6x

​  

=  

4

3y

​  

 

5

6x

​  

−  

4

3y

​  

=0

8x−5y=0...(2)

Multiplying equation (1) by 5  

∴5x+5y=3250...(3)

Adding equations (2) and (3)

∴8x+5y+5x+5y=0+3250

13x=3250

x=Rs250

Substituting the above value in equation (1)

∴250+y=650

∴y=Rs400

∴ Cost price of A=Rs250

∴ Cost price of B=Rs400