Question

A busy is thrown up vertically with a velocity of 200m/s. what time would it take to reach the highest point

Answer 1

Initial velocity is given as 200m/s

Final velocity is 0 m /s at highest point

G is acceleration due ti gravity equal to 10N

We need to find out the highest pointvreached

We use the formula of equations of motion ,

V = u + at

at = v- u
at = -200
-10 ( -ve becoz opposite in direction) × t = -200
T = -200/-10 = 20

Therefore time taken to recah the highest point is 10 seconds

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